Thermal Properties, Heat Transfer, Fluids and Pressure – PHYS 115, Ch. 12.4–12.9, 13.1–13.2 – Study Notes
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Difficulty: Intermediate | Prerequisites: Ch. 11 (first law), Ch. 12.1–12.3 (ideal gas basics)

TL;DR

Materials expand when heated (thermal expansion), absorb specific amounts of heat per degree of temperature change (specific heat), and can change phase at fixed temperatures (heat of transformation). Calorimetry uses energy conservation to find final temperatures when hot and cold objects mix. Heat moves by conduction, convection, and radiation. Fluids exert pressure that increases with depth, and buoyancy is the upward force on submerged objects equal to the weight of displaced fluid.


Key Terms

Specific heat (c)

The amount of heat needed to raise the temperature of 1 kg of a substance by 1 K (or 1°C). Units: J/(kg·K). Different materials have different specific heats; water's is unusually high at 4190 J/(kg·K).

Heat of transformation (L)

The energy per kilogram needed to change a substance's phase (solid to liquid, or liquid to gas) without changing its temperature. Also called latent heat.

Heat of vaporisation

The energy per kilogram to convert liquid to gas (or vice versa). Much larger than the heat of fusion for the same substance.

Thermal expansion

The tendency of materials to increase in size when heated. Applies to length (linear expansion) and volume (volume expansion).

Linear thermal expansion coefficient (α)

ΔL = αLΔT. The fractional change in length per degree of temperature change.

Volume thermal expansion coefficient (β)

ΔV = βVΔT. For isotropic solids, β ≈ 3α.

Bimetallic strip

Two metals bonded together that bend when heated, because they have different expansion coefficients. Used in thermostats.

Calorimetry

The measurement of heat exchange. Based on conservation of energy: all heat lost by hot objects equals the heat gained by cold objects in an isolated system.

Conduction

Heat flow directly through a physical material, from hot regions to cold regions. Rate depends on thermal conductivity, cross-sectional area, temperature difference, and thickness.

Convection

Heat transfer by the bulk movement of a fluid. Occurs when a heated fluid rises and cooler fluid sinks to replace it.

Radiation

Energy emitted by all objects in the form of electromagnetic waves. Does not require a medium. Rate depends on temperature and surface properties.

Diffusion

Net movement of molecules from a region of higher concentration to a region of lower concentration.

Density (ρ)

Mass per unit volume: ρ = m/V. Units: kg/m³.

Buoyant force (F_b)

The upward force exerted by a fluid on a submerged or partially submerged object. F_b = ρ_fluid × V_displaced × g. Equal to the weight of the displaced fluid (Archimedes' principle).

Hydrostatic pressure

Pressure at a depth d in a fluid of uniform density: P = P_surface + ρgd. Pressure increases linearly with depth.


Thermal Expansion (12.4)

Volume thermal expansion

  • ΔV = βVΔT, where β is the coefficient of volume expansion

  • Applies to solids, liquids, and gases

Linear thermal expansion

  • ΔL = αLΔT, where α is the coefficient of linear expansion

  • For isotropic solids: β ≈ 3α

Bimetallic strips

  • Two metals with different α values bonded together

  • When heated, the metal with the higher α expands more, causing the strip to bend

  • If comparing two metals in a thermal expansion diagram, the metal that expanded more has the larger α. This is the basis for simple thermostats.

Example pattern

  • Two cubes of different materials (e.g. aluminium and concrete) with different initial volumes and initial temperatures

  • Find the ratio of their volume changes: ΔV_A / ΔV_B using ΔV = βVΔT for each

  • Pay attention to whether ΔT is the same for both, or different

Specific Heat and Heat of Transformation (12.5)

Specific heat

  • Q = McΔT, where M is mass, c is specific heat, ΔT is temperature change

  • This gives the heat needed to produce a temperature change ΔT for a mass M with specific heat c

  • Molar form: Q = nCΔT, where C is molar specific heat (capital C)

Heat of transformation (phase changes)

  • During a phase change, temperature does not change. All the energy goes into breaking or forming molecular bonds.

  • Q = ML, where L is the latent heat (heat of fusion or heat of vaporisation)

  • Heat of fusion: energy to go from solid to liquid

  • Heat of vaporisation: energy to go from liquid to gas (much larger than heat of fusion)

  • If the process is reversed (gas to liquid, liquid to solid), the same amount of energy is released

Calorimetry (12.6)

Two basic ideas for solving calorimetry problems:

  1. Energy in the system is conserved: Q_net = 0, which means Q_lost + Q_gained = 0

  1. The system reaches thermal equilibrium at some final temperature T_f where all objects have the same temperature

Standard setup (no phase change)

  • M_w c_w (T_f - T_i,w) + M_s c_s (T_f - T_i,s) = 0

  • Solve for T_f

  • The hot object loses heat (its Q is negative), the cold object gains heat (its Q is positive), and they sum to zero

With phase changes

  • If a phase change occurs, you must account for the heat of transformation separately: Q_total = Q_temperature change + Q_phase change

  • Check whether the available energy is sufficient to complete the phase change before assuming the final state

Example from the source notes (Lecture 8, p. 20)

  • 0.120 kg steel pellets at some initial temperature mixed with 0.080 kg of water

  • Boiling water at T = 100°C, water at T = 20°C

  • Heat is transferred between pellets and water; no phase changes occur

  • Set up: M_w c_w (T_f - T_i,w) + M_s c_s (T_f - T_i,s) = 0

  • The source notes flag this concept as important and say to start from the derivations on Lecture 9, page 7

Finding T_f

  • T_f = (M_w c_w T_i,w + M_s c_s T_i,s) / (M_w c_w + M_s c_s)

  • Make sure T is in kelvin or Celsius (not Fahrenheit) and be consistent

Heat Transfer (12.8)

Three mechanisms by which heat moves from one place to another.

Conduction

  • Heat flows directly through a physical material, from hot to cold

  • Rate: Q/Δt = kA(ΔT/L), where k is thermal conductivity, A is cross-sectional area, ΔT is temperature difference, and L is thickness

  • Metals are good conductors; insulators (wood, air, foam) are poor conductors

Convection

  • Heat transfer by the bulk movement of a circulating fluid

  • Occurs when a heated fluid becomes less dense, rises, and is replaced by cooler fluid sinking

  • Natural convection is driven by gravity and density differences; forced convection uses a fan or pump

Radiation

  • Energy emitted by all objects in the form of electromagnetic waves (infrared, visible light, etc.)

  • Does not require a medium; this is how the Sun heats the Earth through the vacuum of space

  • Rate: P = eσAT⁴ (Stefan-Boltzmann law), where e is emissivity (0 to 1), σ = 5.67 × 10⁻⁸ W/(m²·K⁴), A is surface area, T is absolute temperature

  • Net radiation between an object and its surroundings: P_net = eσA(T⁴ - T_surroundings⁴)

Diffusion (12.9)

What it is

  • Net movement of molecules from a region of higher concentration to a region of lower concentration

  • Driven by random molecular motion, not by any external force

Root-mean-square distance

  • r_rms = √(6Dt), where D is the diffusion coefficient and t is time

  • This gives the typical distance a molecule has diffused after time t

  • Diffusion is slow over large distances because it scales with √t, not t

Fick's law

  • Describes the rate of diffusion across a boundary

  • For situations converting between distance, time, and concentration, use the relationship between r_rms and the diffusion coefficient

  • Time to diffuse some distance: t = r² / (6D)

Fluids, Density, Buoyancy and Pressure (13.1, 13.2)

Density

  • ρ = m/V

  • Liquids of uniform density: the density is the same everywhere in the fluid

  • Typical values: ρ_water = 1000 kg/m³, ρ_oil ≈ 900 kg/m³

Pressure in fluids

  • Liquids exert force on the walls of their containers

  • Pressure at all points on a horizontal depth line through a connected fluid of a single kind is the same

  • Pressure increases with depth: P₂ = P₁ + ρgd, where d is the depth below the surface

  • Atmospheric pressure at the surface: P_atm ≈ 1 atm = 1.013 × 10⁵ Pa

Buoyancy (Archimedes' principle)

  • F_b = ρ_fluid × g × V_displaced

  • The buoyant force equals the weight of the displaced fluid

  • An object floats when F_b = W (its weight), which happens when ρ_object < ρ_fluid

  • Maximum displaced volume = V_object (fully submerged). If F_b at full submersion is still less than W, the object sinks.

Two-liquid manometer problems

  • Common exam setup: a U-tube with two liquids that do not mix (e.g. water and oil)

  • One end may be sealed or open to the atmosphere

  • Strategy: find a horizontal level where pressures must be equal, then write P expressions for each side at that level

  • Example pattern from the source notes:

    • P₁ = P_atm + ρ_oil × g × h_oil (open side)

    • P₂ = P_atm + ρ_water × g × h_water (other side)

    • Set P₁ = P₂ at the same horizontal level and solve

Biology application (from Lecture 11, p. 23)

  • Pressure differences in biological systems (blood pressure, pressure in lungs) follow the same hydrostatic pressure formula

  • The source notes flag a biology question from this lecture as exam-relevant


Formulas and Key Equations

Q = Mc\Delta T \quad \text{(specific heat)}
Q = ML \quad \text{(phase change)}
\Delta L = \alpha L \Delta T \quad ; \quad \Delta V = \beta V \Delta T
\frac{Q}{\Delta t} = \frac{kA\Delta T}{L} \quad \text{(conduction)}
P = e\sigma A T^4 \quad \text{(radiation, Stefan-Boltzmann)}
r_{rms} = \sqrt{6Dt} \quad \text{(diffusion)}
P_2 = P_1 + \rho g d \quad \text{(hydrostatic pressure)}
F_b = \rho_{fluid} \cdot g \cdot V_{displaced} \quad \text{(buoyancy)}
T_f = \frac{M_1 c_1 T_1 + M_2 c_2 T_2}{M_1 c_1 + M_2 c_2} \quad \text{(calorimetry, no phase change)}

Real-World Applications

  • Bimetallic strips are the working principle behind older thermostats and some circuit breakers. When the strip bends past a threshold, it makes or breaks an electrical contact.

  • Car radiators rely on all three heat transfer mechanisms: conduction through the metal fins, convection as air flows past them, and radiation from the hot surfaces. The fins increase surface area to maximise conduction and convection.

  • Diffusion governs how oxygen moves from your lungs into your blood and how ink spreads in still water. The √t scaling explains why diffusion works well over short distances (cells) but is far too slow for transporting substances across an entire body.


Common Misconceptions

  • Students often assume that during a phase change, temperature rises. It does not. All the energy goes into breaking molecular bonds until the phase change is complete.

  • Students sometimes think buoyant force depends on the object's mass. It does not. It depends on the volume of fluid displaced and the density of the fluid.

  • Students confuse conduction and convection. Conduction is heat moving through a stationary material. Convection requires the material itself to move.

  • Students occasionally think radiation requires air or some medium. It does not. Radiation travels through vacuum, which is how the Sun heats the Earth.


Why It Matters / Exam Flags

  • ⚠️ Calorimetry problems (mixing hot and cold objects) are a staple of this exam. Know how to set up Q_lost + Q_gained = 0 and solve for T_f.

  • ⚠️ The two-liquid U-tube manometer problem is highlighted in the source notes. Know how to equate pressures at the same horizontal level.

  • ⚠️ Thermal expansion comparison problems (which material expands more) appear frequently. Remember: ΔV = βVΔT, so you need to compare β, V, and ΔT for each material.

  • ⚠️ Know the three heat transfer mechanisms and be able to identify which is operating in a given scenario.

  • ⚠️ The biology question from Lecture 11, p. 23, is flagged as exam-relevant. Review pressure in biological systems.


Quick Self-Test

  1. True or False: During a phase change, the temperature of the substance increases. (False. Temperature stays constant during a phase change.)

  1. Fill in the blank: The buoyant force on an object equals the weight of the ______ ______. (displaced fluid)

  1. True or False: Convection can occur in a solid. (False. Convection requires fluid flow.)

  1. Fill in the blank: Pressure in a fluid increases with ______. (depth)

  1. True or False: The root-mean-square diffusion distance scales linearly with time. (False. It scales with √t.)


Practice Q&A

Q: A 0.5 kg aluminium block (c = 900 J/(kg·K)) at 200°C is dropped into 2 kg of water (c = 4190 J/(kg·K)) at 20°C. What is the final equilibrium temperature?

A: M_Al × c_Al × (T_f - 200) + M_w × c_w × (T_f - 20) = 0. Solving: 0.5(900)(T_f - 200) + 2(4190)(T_f - 20) = 0. So 450T_f - 90000 + 8380T_f - 167600 = 0. Therefore 8830T_f = 257600, giving T_f ≈ 29.2°C.

Q: A wooden block (ρ = 600 kg/m³) with volume 0.01 m³ is placed in water (ρ = 1000 kg/m³). Does it float? If so, what fraction is submerged?

A: ρ_block < ρ_water, so it floats. At equilibrium, F_b = W: ρ_water × g × V_submerged = ρ_block × g × V_block. So V_submerged / V_block = ρ_block / ρ_water = 600/1000 = 0.6. 60% is submerged.

Q: A copper rod (k = 400 W/(m·K)) is 0.5 m long with a cross-section of 0.001 m². One end is at 100°C, the other at 20°C. What is the rate of heat conduction?

A: Q/Δt = kAΔT/L = 400 × 0.001 × (100 - 20) / 0.5 = 400 × 0.001 × 80 / 0.5 = 64 W.

Q: If a molecule takes 10 seconds to diffuse 1 mm, roughly how long will it take to diffuse 1 cm?

A: Distance scales as √t, so if you multiply distance by 10, time multiplies by 100. About 1000 seconds.

Q: In a U-tube with water on one side and oil (ρ = 900 kg/m³) on the other, both open to the atmosphere, the oil column is 10 cm taller than the water column. What is the height of the water column?

A: At the interface level: P_atm + ρ_oil × g × h_oil = P_atm + ρ_water × g × h_water. The atmospheric terms cancel. ρ_oil × h_oil = ρ_water × h_water. If h_oil = h_water + 0.10, then 900(h_water + 0.10) = 1000 × h_water. Solving: 900h + 90 = 1000h, so 100h = 90, h_water = 0.90 m = 90 cm.


Connections to Other Topics

  • Calorimetry is a direct application of the first law of thermodynamics (Ch. 11.4) to systems where heat is the only energy transfer.

  • Heat transfer mechanisms (conduction, convection, radiation) explain why the second law of thermodynamics always holds in practice: there are always pathways for energy to spread out.

  • Fluid pressure and buoyancy connect to forces and Newton's laws from earlier in the course. The buoyant force is just the net upward pressure force on a submerged object.


Related Terms / Search Tags

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