Limits: Definition, Existence, and Evaluation Techniques – CALC 157, Lessons 1–3 – Study Notes

Source: Lecture notes #21, Texas A&M University

Tags: limits, limit definition, limit existence, one-sided limits, evaluating limits, substitution, factoring, conjugate method, holes in graphs, calculus 1, CALC 157


TL;DR

A limit describes the y-value a function is heading towards as x approaches a particular number, regardless of whether the function actually reaches that value. A limit exists only when both the left-hand and right-hand limits agree. You can evaluate most limits through direct substitution, factoring to cancel problem terms, or multiplying by a conjugate.


Key Terms

Limit

The height (y-value) a function is intended to reach as x approaches a given value. Written as lim f(x) as x → c.

One-sided limit (left-hand limit)

The value a function approaches as x comes from the left (values less than c). Written as lim f(x) as x → c⁻.

One-sided limit (right-hand limit)

The value a function approaches as x comes from the right (values greater than c). Written as lim f(x) as x → c⁺.

Hole (removable discontinuity)

A point where a function is undefined or differs from the limit, but the limit itself still exists. On a graph, shown as an open circle.

DNE (Does Not Exist)

Used when a limit cannot be determined, typically because the left-hand and right-hand limits disagree.


Core Content

Lesson 1 – What a Limit Actually Is

  • A limit is the y-value a function intends to reach as x approaches a specific number.

  • It does not matter whether the function actually arrives at that value. What matters is the trend.

Example with f(x) = x²:

  • Different x-values produce different heights.

  • When x = 2, y = 4, so lim f(x) as x → 2 = 4.

Example with a hole:

  • Consider (x² – 6x + 8) / (x – 2), which factors to (x – 4)(x – 2) / (x – 2).

  • At x = 2, the function is undefined (division by zero), creating a hole at (2, –2).

  • The limit still exists at x = 2 because the function is heading towards –2 from both sides.

  • lim g(x) as x → 2 = –2, even though g(2) is undefined.

Lesson 2 – When a Limit Exists (and When It Does Not)

  • A limit exists when you approach a single point from both sides of the x/y axes and get the same value.

  • A limit does not exist when the function "breaks," i.e. the left-hand and right-hand limits disagree.

How to check:

  • Evaluate the left-hand limit (approaching from below).

  • Evaluate the right-hand limit (approaching from above).

  • If they match, the general limit equals that shared value.

  • If they differ, the limit DNE.

Example of DNE:

  • If lim f(x) as x → 4⁺ = 2 (from the right) and lim f(x) as x → 4⁻ = 1 (from the left), the values do not match, so lim f(x) as x → 4 = DNE.

Key rule: A limit can still exist when there is a hole on the graph. Holes affect function value, not limit value.

Lesson 3 – How to Evaluate Limits

Three core techniques, in order of complexity:

Technique 1 – Direct substitution

  • Plug the target x-value directly into the function.

  • If you get a real number (no division by zero, no 0/0), that is the limit.

  • Example: lim (x² – 1) / (2x + 3) as x → 0 = (0 – 1) / (0 + 3) = –1/3.

Technique 2 – Factoring

  • Use this when substitution gives 0/0 (an indeterminate form).

  • Factor the numerator and denominator, cancel the common factor, then substitute.

  • Example: lim (x² – 6x + 8) / (x – 2) as x → 2

    • Factor: (x – 4)(x – 2) / (x – 2)

    • Cancel (x – 2): leaves (x – 4)

    • Substitute x = 2: 2 – 4 = –2

    • lim = –2

Technique 3 – The conjugate method

  • Use this when the expression contains a square root and substitution gives 0/0.

  • Multiply the numerator and denominator by the conjugate of the radical expression.

  • Example: lim (√x – 4) / (x – 16) as x → 16

    • Multiply top and bottom by (√x + 4)

    • Numerator becomes: x – 16 (difference of squares)

    • Simplifies to: 1 / (√x + 4)

    • Substitute x = 16: 1 / (√16 + 4) = 1 / (4 + 4) = 1/8


Formulas / Diagrams

Limit notation:

lim f(x) as x → c = L

Factoring pattern (difference of squares / quadratic):

x² – 6x + 8 = (x – 4)(x – 2)

Conjugate identity:

(√a – b)(√a + b) = a – b²


Why It Matters / Exam Flags

⚠️ A limit can exist even when the function is undefined at that point. Holes do not kill limits.

⚠️ Always try substitution first. Factoring and the conjugate method are for when substitution returns 0/0.

⚠️ "DNE" only applies when left-hand and right-hand limits disagree, or when the function heads to infinity (covered in Lesson 4).

⚠️ When using the conjugate method, make sure you multiply both the numerator and the denominator, not just one.

⚠️ After factoring and cancelling, you must still substitute the x-value to get the final answer.


Practice Q&A

Q: What is a limit in plain terms?

A: The y-value a function is heading towards as x gets closer to a particular number, whether or not it actually reaches that value.

Q: If f(2) is undefined, can lim f(x) as x → 2 still exist?

A: Yes. A limit depends on the values the function approaches near x = 2, not the value at x = 2 itself. A hole does not prevent the limit from existing.

Q: When does a limit not exist?

A: When the left-hand limit and the right-hand limit are different values (they do not agree), or when the function increases or decreases without bound.

Q: Evaluate lim (x² – 6x + 8) / (x – 2) as x → 2.

A: Factor to (x – 4)(x – 2) / (x – 2), cancel (x – 2), substitute x = 2 into (x – 4) to get –2.

Q: When should you use the conjugate method?

A: When the expression involves a square root and direct substitution gives the indeterminate form 0/0. Multiply by the conjugate to eliminate the radical.

Q: Evaluate lim (√x – 4) / (x – 16) as x → 16.

A: Multiply by (√x + 4)/(√x + 4). Numerator becomes x – 16, which cancels with the denominator. Left with 1/(√x + 4). Substitute x = 16 to get 1/8.


Related Terms / Search Tags

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