Derivatives of Trigonometric Functions, MTH 132 Section 2.4 – Study Notes
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Difficulty: Intermediate | Prerequisites: Product rule, quotient rule, basic trig identities, Section 2.3 notes.

TL;DR

Differentiating trigonometric functions means applying the product rule and quotient rule alongside the two base derivatives: (sin x)′ = cos x and (cos x)′ = −sin x. From those two, every other trig derivative (tan, sec, csc, cot) can be derived. The section also covers tangent line equations, which combine evaluation with differentiation.

Key Terms


Product rule

If f(x) = g(x) · h(x), then f′(x) = g′(x) · h(x) + g(x) · h′(x). Think of it as: differentiate the first and leave the second alone, then leave the first alone and differentiate the second, then add.

Quotient rule

If f(x) = g(x)/h(x), then f′(x) = [g′(x) · h(x) − g(x) · h′(x)] / [h(x)]². Think of it as: "low d-high minus high d-low, over the square of what's below."

Tangent line

The line that touches a curve at exactly one point and has slope equal to the derivative at that point. The equation is y − f(a) = f′(a)(x − a).

sec(x)

sec(x) = 1/cos(x). Its derivative is sec(x) tan(x). This comes up frequently when differentiating tan(x) or expressions involving 1/cos(x).


Core Content


Product Rule with Trig Functions

When a function is the product of two pieces (one or both involving trig), apply the product rule. For products of three factors, apply the rule iteratively or use the extended product rule.

  • Example (a): f(x) = ³√x · sec(x) = x^(1/3) sec(x)

    • f′(x) = (1/3)x^(−2/3) sec(x) + x^(1/3) sec(x) tan(x)

    • The first term differentiates the power; the second differentiates the sec.

  • Example (b): g(x) = x² cos(x) − x^(1/4)

    • g′(x) = 2x cos(x) + x²(−sin(x)) − (1/4)x^(−3/4)

    • The product rule applies only to x² cos(x); the −x^(1/4) term differentiates separately.

  • Example (e): f(x) = −3x sin(x) cos(x)

    • This is a product of three factors: (−3x), sin(x), cos(x).

    • f′(x) = −3 sin(x) cos(x) − 3x cos(x) cos(x) − 3x sin(x)(−sin(x))

    • Simplifies to: −3 sin(x) cos(x) − 3x cos²(x) + 3x sin²(x)

Quotient Rule with Trig Functions

Use the quotient rule whenever a trig function sits in the denominator.

  • Example (c): h(x) = x³ / (10 + tan(x))

    • h′(x) = [3x²(10 + tan(x)) − x³ sec²(x)] / (10 + tan(x))²

    • The numerator follows "low d-high minus high d-low" exactly.

  • Example (d): p(t) = (2 tan(t) + 2) / sec(t)

    • p′(t) = [2 sec²(t) · sec(t) − (2 tan(t) + 2) · sec(t) tan(t)] / sec²(t)

Deriving the Derivative of tan(x)

Problem 6 asks you to prove (tan x)′ = sec²(x) using the quotient rule. This is a common exam proof.

  • Write tan(x) = sin(x)/cos(x)

  • Apply the quotient rule: [cos(x) · cos(x) − sin(x) · (−sin(x))] / cos²(x)

  • Numerator simplifies: cos²(x) + sin²(x) = 1

  • Result: 1/cos²(x) = sec²(x)

Tangent Line Equations

To find the equation of the tangent line at x = a:

  1. Compute f(a) to find the y-coordinate of the point.

  1. Compute f′(a) to find the slope.

  1. Write the line: y − f(a) = f′(a)(x − a).

  • Example: f(x) = cos(x) + sec(x) at x = π

    • f(π) = cos(π) + sec(π) = −1 + (−1) = −2

    • f′(x) = −sin(x) + sec(x) tan(x)

    • f′(π) = −sin(π) + sec(π) tan(π) = 0 + 0 = 0

    • Tangent line: y + 2 = 0(x − π), which gives y = −2

    • A horizontal tangent line, which means the curve has a local extremum at x = π.


Formulas


\frac{d}{dx}[\sin x] = \cos x
\frac{d}{dx}[\cos x] = -\sin x
\frac{d}{dx}[\tan x] = \sec^2 x
\frac{d}{dx}[\sec x] = \sec x \tan x

Product rule:

(fg)' = f'g + fg'

Quotient rule:

\left(\frac{f}{g}\right)' = \frac{f'g - fg'}{g^2}

Tangent line at x = a:

y - f(a) = f'(a)(x - a)

Real-world Applications

Derivatives of trig functions describe rates of change in oscillating systems. The velocity of a weight on a spring, the current in an AC circuit, and the rate of change of daylight hours through the year are all modelled by derivatives of sine and cosine.


Common Misconceptions

  • Students often write (cos x)′ = sin x, forgetting the negative sign. The derivative of cosine is negative sine.

  • When applying the product rule to three factors, students frequently differentiate only two of them. Each factor gets its turn being differentiated while the other two are left alone, giving three terms.

  • Students sometimes apply the quotient rule but reverse the order in the numerator. The correct order is (bottom × derivative of top) minus (top × derivative of bottom), not the other way round.

  • When finding tangent lines, students compute f′(a) but forget to also evaluate f(a) for the point itself.


Why It Matters / Exam Flags

⚠️ Expect at least one product rule problem and one quotient rule problem involving trig on Exam 2.

⚠️ The proof that (tan x)′ = sec²(x) is a classic "show your work" question. Know it cold.

⚠️ Tangent line problems combine two skills (evaluate and differentiate), so they are a favourite for testing overall fluency.

⚠️ Watch for problems where the slope turns out to be zero (horizontal tangent). This is not an error; it means the curve is flat at that point.


Quick Self-test

  1. True or false: The derivative of cos(x) is sin(x).

    • False. It is −sin(x).

  1. Fill in the blank: The quotient rule numerator is (low × d-high) ___ (high × d-low).

    • Minus.

  1. True or false: sec²(x) = 1/cos²(x).

    • True.

  1. Fill in the blank: The tangent line to f at x = a has slope ___.

    • f′(a).

  1. True or false: If f′(a) = 0, there is no tangent line at x = a.

    • False. The tangent line is horizontal (slope zero).


Practice Q&A

Q: Find f′(x) if f(x) = ³√x sec(x).

A: Write f(x) = x^(1/3) sec(x). By the product rule: f′(x) = (1/3)x^(−2/3) sec(x) + x^(1/3) sec(x) tan(x).

Q: Differentiate h(x) = x³ / (10 + tan(x)).

A: By the quotient rule: h′(x) = [3x²(10 + tan(x)) − x³ sec²(x)] / (10 + tan(x))².

Q: Use the quotient rule to show that (tan x)′ = sec²(x).

A: tan(x) = sin(x)/cos(x). Quotient rule gives [cos(x) cos(x) − sin(x)(−sin(x))] / cos²(x) = [cos²(x) + sin²(x)] / cos²(x) = 1/cos²(x) = sec²(x).

Q: Find the tangent line to f(x) = cos(x) + sec(x) at x = π.

A: f(π) = −1 + (−1) = −2. f′(π) = −sin(π) + sec(π)tan(π) = 0. The tangent line is y = −2.

Q: Differentiate f(x) = −3x sin(x) cos(x).

A: Apply the product rule to three factors: f′(x) = −3 sin(x) cos(x) − 3x cos²(x) + 3x sin²(x).


Connections to Other Topics

These derivative techniques lead directly into the chain rule (next section), where you will differentiate compositions like sin(x²) or cos(3x + 1). The tangent line equation also reappears in linear approximation and differentials later in the course.


Related Terms / Search Tags

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