Arc Length and Arc Length Parametrisation, MATH 215 §13.3 – Study Notes
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Source: Homework Set 3, §13.1–13.4

Tags: arc length, arc length parametrisation, arc length function, speed, unit speed, Calculus III, MATH 215

Difficulty: Intermediate | Prerequisites: Integration techniques (especially trig identities and substitution), vector-valued functions (§13.1–13.2).

Big Picture

Arc length measures the actual distance along a curve, regardless of how fast a particle traverses it. This is the geometric length of the path. Arc length parametrisation is a way to reparametrise a curve so that the parameter itself measures distance along the curve, which simplifies many later formulas (curvature, for instance). If you are comfortable with the magnitude of a derivative and with definite integrals, you are ready.


TL;DR

The length of a parametric curve is the integral of |r'(t)| over the parameter interval. The arc length function s(t) accumulates distance from a starting point. If you can invert s(t) to get t(s), you can reparametrise the curve by arc length, giving a unit-speed traversal.

Key Terms

Arc length

The total distance along a curve between two points. Computed as the integral of the speed |r'(t)| over the parameter interval. Think of it as laying a string along the curve and measuring how long the string is.

Speed (of a parametrisation)

The magnitude |r'(t)| of the velocity vector. This tells you how fast a point is moving along the curve at parameter value t. Not the same as the velocity vector itself, which also carries directional information.

Arc length function s(t)

Defined as s(t) = ∫ from a to t of |r'(u)| du. It gives the distance travelled along the curve from the starting point r(a) to the current point r(t). In simple terms, s(t) is a running total of distance.

Arc length parametrisation

A reparametrisation of the curve where the parameter s represents distance along the curve. In an arc length parametrisation, |r'(s)| = 1 at every point, meaning the curve is traversed at unit speed. Think of it as a "constant pace" walk along the curve where each unit of parameter equals one unit of distance.

Reparametrisation

Replacing the parameter t with a new parameter (often s) via a substitution t = t(s). The curve itself does not change, only the "clock" that tracks position along it.

Core Content: Computing Arc Length

The Arc Length Integral

  • For a curve r(t) = ⟨f(t), g(t), h(t)⟩ on [a, b], the arc length is:

    • L = ∫ from a to b of |r'(t)| dt = ∫ from a to b of √(f'(t)² + g'(t)² + h'(t)²) dt.

  • The key step is computing |r'(t)| and simplifying before integrating. Trig identities are often essential.

Worked Example: r(t) = ⟨sin³(t), cos³(t), sin²(t)⟩ on [0, π]

  • r'(t) = ⟨3sin²(t)cos(t), −3cos²(t)sin(t), 2sin(t)cos(t)⟩.

  • |r'(t)|² = 9sin⁴(t)cos²(t) + 9cos⁴(t)sin²(t) + 4sin²(t)cos²(t).

  • Factor: = sin²(t)cos²(t)(9sin²(t) + 9cos²(t) + 4) = sin²(t)cos²(t)(9 + 4) = 13sin²(t)cos²(t).

  • So |r'(t)| = √13 · |sin(t)cos(t)| = (√13/2)|sin(2t)|.

  • On [0, π], sin(2t) changes sign at t = π/2. Split the integral:

    • L = (√13/2)[∫ from 0 to π/2 of sin(2t) dt + ∫ from π/2 to π of (−sin(2t)) dt] = (√13/2)[1 + 1] = √13.

Tips for Arc Length Computations

  • Always simplify |r'(t)|² before taking the square root. Factor aggressively.

  • Watch for absolute values when simplifying square roots. |sin(t)cos(t)| ≠ sin(t)cos(t) everywhere.

  • Common identities that appear: sin²(t) + cos²(t) = 1, double angle sin(2t) = 2sin(t)cos(t), half-angle formulas.

Core Content: Arc Length Parametrisation

The Process

  • Start with a parametric curve r(t) and compute the arc length function s(t) = ∫ from −∞ (or a) to t of |r'(u)| du.

  • Invert: solve for t as a function of s, giving t = t(s).

  • Substitute back: replace t with t(s) in the original parametrisation to get r(s) = r(t(s)).

  • The result is a curve parametrised by arc length, where |r'(s)| = 1.

Worked Example: x(t) = 2/(t² + 1) − 1, y(t) = 2t/(t² + 1)

  • Compute derivatives: x'(t) = −4t/(t² + 1)², y'(t) = 2(1 − t²)/(t² + 1)².

  • |r'(t)|² = [16t² + 4(1 − t²)²] / (t² + 1)⁴ = [16t² + 4 − 8t² + 4t⁴] / (t² + 1)⁴.

  • Simplify: = [4t⁴ + 8t² + 4] / (t² + 1)⁴ = 4(t² + 1)² / (t² + 1)⁴ = 4/(t² + 1)².

  • So |r'(t)| = 2/(t² + 1).

  • The arc length function: s(t) = ∫ from −∞ to t of 2/(u² + 1) du = 2 arctan(t) + π (since arctan(−∞) = −π/2).

  • Invert: arctan(t) = (s − π)/2, so t = tan((s − π)/2).

  • Substitute back into x(t) and y(t). Using the identity cos(θ) = (1 − tan²(θ/2))/(1 + tan²(θ/2)) and sin(θ) = 2tan(θ/2)/(1 + tan²(θ/2)) with appropriate substitution, you get x(s) = cos(s − π) = −cos(s) and y(s) = sin(s − π) = −sin(s), or equivalently x(s) = −cos(s), y(s) = −sin(s).

  • This is a unit circle. The original curve was a unit circle all along, just parametrised non-uniformly. The arc length parametrisation reveals it as uniform motion around the circle.

Why Arc Length Parametrisation Matters

  • It separates geometry from speed. The shape of the curve is purely geometric; how fast you traverse it is a choice. Arc length parametrisation chooses unit speed.

  • Curvature formulas (§13.4) are simplest in arc length parametrisation: κ = |T'(s)|.

  • Not every curve has a closed-form arc length parametrisation. When it does, consider it a gift.

Formulas

L = \int_a^b |\mathbf{r}'(t)|\, dt = \int_a^b \sqrt{f'(t)^2 + g'(t)^2 + h'(t)^2}\, dt
s(t) = \int_a^t |\mathbf{r}'(u)|\, du
\frac{ds}{dt} = |\mathbf{r}'(t)| \quad \text{(speed)}

In an arc length parametrisation: |r'(s)| = 1 for all s.

Real-World Applications

Arc length is how you measure the actual distance of a road, a wire, a pipe, or a flight path. GPS devices compute arc length along your route. In physics, if a particle moves along a curve, the arc length tells you the distance travelled regardless of how the motion was parametrised (fast, slow, or variable speed).


Common Misconceptions

  • Students often forget the absolute value in |r'(t)| when simplifying. After taking a square root, you get |sin(t)cos(t)|, not sin(t)cos(t). Dropping the absolute value gives the wrong answer when the expression is negative.

  • Confusing the arc length (a number) with the arc length function (a function of t). The arc length of a curve on [a, b] is a single number L. The arc length function s(t) is a running total that depends on t.

  • Assuming that every curve can be reparametrised by arc length in closed form. Most cannot. The process is conceptually clean but the integrals are often intractable.

  • Treating the parameter t as distance. Unless you have specifically reparametrised by arc length, a change of 1 in t does not correspond to a distance of 1 along the curve.


Why It Matters / Exam Flags

⚠️ Arc length integrals are a staple exam problem. The main challenge is simplifying |r'(t)| before integrating. Practice trig identity manipulation.

⚠️ The full arc length parametrisation process (compute s(t), invert, substitute) is a multi-step problem that tests several skills at once. Know each step cold.

⚠️ Watch for absolute values. Splitting integrals at points where expressions change sign is frequently tested.

Quick Self-Test

  1. The arc length of a curve is computed by integrating ___ over the parameter interval.

  1. True or false: In an arc length parametrisation, |r'(s)| can vary. ___

  1. The arc length function s(t) represents ___.

  1. True or false: To reparametrise by arc length, you must be able to invert s(t). ___

  1. After simplifying |r'(t)|², you should take the square root and include ___.

Answers: 1. |r'(t)| (the speed). 2. False (|r'(s)| = 1 always). 3. The cumulative distance from the starting point to r(t). 4. True. 5. Absolute values where needed.


Practice Q&A

Q: Compute the arc length of r(t) = ⟨cos(t), sin(t), t⟩ on [0, 2π].

A: r'(t) = ⟨−sin(t), cos(t), 1⟩. |r'(t)| = √(sin²(t) + cos²(t) + 1) = √2. L = ∫ from 0 to 2π of √2 dt = 2π√2.

Q: For the curve x(t) = 2/(t² + 1) − 1, y(t) = 2t/(t² + 1), what is the speed |r'(t)|?

A: |r'(t)| = 2/(t² + 1). This comes from computing x'(t)² + y'(t)² and simplifying.

Q: After computing s(t) = 2arctan(t) + π, invert to find t as a function of s.

A: arctan(t) = (s − π)/2, so t = tan((s − π)/2).

Q: Why is arc length parametrisation useful for computing curvature?

A: In arc length parametrisation, curvature simplifies to κ = |T'(s)| = |r''(s)|. Without it, you need the more complex cross-product formula κ = |r'(t) × r''(t)| / |r'(t)|³.

Connections to Other Topics

Arc length connects directly to curvature (§13.4), which measures how much a curve bends per unit length. It also connects back to tangent vectors (§13.2), since the speed ds/dt = |r'(t)| is the magnitude of the tangent vector. In later chapters, arc length appears again in line integrals (Chapter 16), where you integrate a function along a curve weighted by arc length.


Related Terms / Search Tags

Arc length, arc length integral, arc length function, arc length parametrisation, reparametrisation, unit speed, speed of a curve, |r'(t)|, distance along a curve, curvature, trig identities, absolute value in integrals, MATH 215, Calculus III, §13.3